Calc 1 Find the derivative dy/dx y=e^(sinh(x)) Calculas find the compute derivative of f(x)=sinh^2(5x) math , probability Let X and Y be two independent and identically distributed random variables that take only positive integer values Their PMF is px (n) = py (n) = 2^n for every n e N, where N is the set of positive integers dy/dx = (dy/dt) / (dx/dt) = (2)/(2t) = 1/t check t = (4y)/2 x = t^2 = (4y)^2/4 dx/dy = (4y)/2 dy/dx = 2/(4y) = 2/(4 (42t)) = 2/(2t) = 1/tIf 3 By 2 Plus I Root3 By 2 Power 50 Equal 3 25 X Iy Where X And Y Are Real Then The Ordered Pair X Y Is
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Y=x^2+1/x^2 find dy/dx-If 2x 2 3xy y 2 x 2y 8 = 0, then dy/dx is equal to If 3 ≤ 3t 18 ≤ 18, then which one of the following is correct? Find dy/dx if y = cos1((1 x2)/(1 x2)), 0 < x < 1 Welcome to Sarthaks eConnect A unique platform where students can interact with
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If (x^2y^2)^2=xy , find dy/dx Get the answers you need, now!Share It On Facebook Twitter Email 1 Answer 1 vote answered by Prerna01 (521k points) selected by RahulYadav Best answer Given (x y) 2 = 2axy Differentiating the equation on both sides with respect to x, ← Prev2xy9x^2 (2yx^21) (dy)/ (dx)=0, y (0)=3 \square!
Answer (1 of 7) (xy)^2 \dfrac{dy}{dx}=1 \implies (xy)^2 \left\dfrac{d(xy)}{dx}1 \right=1 \implies (xy)^2\dfrac{d(xy)}{dx}(xy)^2=1 \implies \dfrac{(xy)^2 dSolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more Ex 53, 11 Find 𝑑𝑦/𝑑𝑥 in, 𝑦 = cos–1 ((1− 𝑥^2)/( 1 𝑥2 )) , 0 < x < 1 𝑦 = cos–1 ((1− 𝑥^2)/( 1 𝑥2 )) Putting x = tan θ y
Join this channel to get access to perkshttps//wwwyoutubecom/channel/UCFhqELShDKKPv0JRCDQgFoQ/joinHere is the technique to solve this nonlinear ordinary Find dy/dx (x y) 2 = 2axy differentiation;X\frac{dy}{dx}=y^{2} en Related Symbolab blog posts Advanced Math Solutions – Ordinary Differential Equations Calculator, Exact Differential Equations In the previous posts, we have covered three types of ordinary differential equations, (ODE) We have now reached
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Find dy/dx y^2=(x1)/(x1) Differentiate both sides of the equation Differentiate the left side of the equation Tap for more steps Differentiate using the chain rule, which states that is where and Tap for more steps To apply the Chain Rule, set asCalculus Find dy/dx y^2=1/ (1x^2) y2 = 1 1 − x2 y 2 = 1 1 x 2 Differentiate both sides of the equation d dx (y2) = d dx ( 1 1−x2) d d x ( y 2) = d d x ( 1 1 x 2) Differentiate the left side of the equation Tap for more steps dy/dx=3x^212x11 >"expanding the factors gives" y=x^36x^211x6 "differentiate each term using the "color(blue)"power rule" •color(white)(x)d/dx(ax^n)=nax^(n1
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The derivative of y dy/dx becomes d y/dx = sY y (0) where y (0) is the value of y when x is 0 and the second derivative of y with respect to x d^y/dx^2 becomes d^2 y/dx^2= (s^2)Ys ( y (0)) dy/dx where dy/dx is the value of the first derivative at Haryana School reopening from th September for Classes 1 to 3 Know school reopening guidelines, reduced syllabus and FAQs THE World University Rankings 22 by Subject has been released for Physical Sciences, Life Sciences, Psychology, and Clinical and Health Rajasthan board 22 crash course for English mediumSee Page 1 your answer in the simplest form Hence evaluate dy dx when 1 x Ans 2 1 ln dy y dx x y x , 1 4 dy dx 17 Find dy dx for 2 2 2 2 y x y y e by using implicit differentiation Ans 2 2 y dy xy dx x y e 18 Find dy dx for 3 2 4 2 2 y y x y xe by using implicit differentiation
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Y= (1X)^1/2 / (1X)^1/2 Using division rule which is dy/dx= (g (X)d/dx f (X) — f (X)d/dxg (X))/ g (X)2 Where f (X) is first function and g (X) is is second function Also use power rule (f (X))^n = nf (X)^n1 dy/dx= ( (x1)^1/2 (1/2 (x1)^1/2 — (x1)^1/2 (1/2 (xFor the differential equation `(x^2y^2)dx2xy dy=0`, which of the following are true (A) solution is `x^2y^2=cx` (B) `x^2y^2=cx` `x^2y^2=xc` (D) `yFind Dy/Dx for Y = Sec^(1) (1/(2x^2 1)), 0 < X < 1/Sqrt2 CBSE CBSE (Arts) Class 12 Question Papers 17 Textbook Solutions MCQ Online Tests 1 Important Solutions 24 Question Bank Solutions 199 Concept Notes & Videos 532
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If y = (1 1/x2)/(1 1/x2), then dy/dx is Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to Explanation Differentiating both sides of the equation with respect to x we have 1 = 2y dy dx dy dx = 1 2y Now, as x = y2 1 > 1 we have yGet stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!
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Cost of 18 shirts and 45 trousers isRs 68,400/ What is the cost of 10 shirts and25 trousers?A Rs 38,000/C Rs 34,0/EIf y = 2^x, find dy/dx Q If y = 2^x, find dy/dx ANSWER 1) Take Logs of both sides of our equation y = 2^x So we get log (y)=log (2^x) 2) Apply relevant log rule to rhs Log rule log (a^b) = b log (a) nb the dot between b and log (a) represents x / multiply / Transcribed image text 1) Find dy/dx y=3x2 5x2 2) Find dy/dx y = 8x7x42x) 3) Find dy/dx 2 4) Find dy/dx y=5x43x31 5) Find dy/dx 2 6) Find dy/dx y (85x2)(3x2 60) 7) Find dy/d>x y (5x 6)(3 4x3) 8) Find dy/dx y=(5x 6)2 9) Find dy/dx y=(x23x 2)(4x3x2 5) 10) Find dy/dx X 6 x 6
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Now how did I know that, becuase `dy/dx` is 3x 2 2, y must be the integral of 3x 2 2 `dy/dx` differentiation and integration are opposite processes Ok, so I just integrate this and I get `x^3/3`, and there is 3 on the front, so the 3 cancels out so I just get x 3 2x KCalculus Find dy/dx y= (x1)/ (x2) y = x 1 x 2 y = x 1 x 2 Differentiate both sides of the equation d dx (y) = d dx ( x 1 x 2) d d x ( y) = d d x ( x 1 x 2) The derivative of y y with respect to x x is y' y ′ y' y ′ Differentiate the right side of the equation Tap for more steps Find dy/dx of x = 3 cos θ 2 cos3 θ, y = 3 sin θ 2 sin3 θ expressed in para metric form asked in Class XII Maths by nikita74 Expert (112k points) continuity and differentiability 0 votes 1 answer Find dy/dx sin x = 2t/1t2,tan y = 2t/1t2 expressed in parametric form
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Since 2 2 is constant with respect to x x, the derivative of 2 2 with respect to x x is 0 0 2 x 0 2 x 0 Add 2 x 2 x and 0 0 2 x 2 x 2x 2 x Reform the equation by setting the left side equal to the right side y' = 2x y ′ = 2 x Replace y' y ′ with dy dx d y d x dy dx = 2x d y d x = 2 xKCET 15 If y= log ( (1x2/1x2)) then (dy/dx) is equal to (A) (4x/1x4) (B) (4x3/1x4) (1/4x4) (D) (4x3/1x4) Check Answer and SolutDifferentiate wrtx dy/dx = ((1x)x)/(1x) 2 = (1xx)/(1x) 2 = 1/(1x) 2 Hence option (2) is the answer Was this answer helpful?
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1) dy/dx y = e^2 2) dy/dx 2xsiny /x cosy = 0 3) dy/dx 5y = 0 4) dy/dx y = 2x 5) dy/dx y = cosx 6) dy/dx x^2y1 / x = 0 (x>0) Ex 94, 12 Find a particular solution satisfying the given condition 𝑥 𝑥2−1 𝑑𝑦𝑑𝑥=1;𝑦=0 When 𝑥=2 𝑥 𝑥2−1 dy = dx dy = 𝑑𝑥𝑥(𝑥2 − 1) Integrating both sides 𝑑𝑦 = 𝑑𝑥𝑥(𝑥2 − 1) 𝑦 = 𝑑𝑥𝑥(𝑥 1)(𝑥 − 1) We can write integrand as 1𝑥(𝑥 1 Ex 53, 15 Find 𝑑𝑦/𝑑𝑥 in, y = sec–1 (1/( 2𝑥2−1 )), 0 < x < 1/√2 y = sec–1 (1/( 2𝑥^2 − 1 )) 𝒔𝒆𝒄𝒚 = 1/(2𝑥^2 − 1) 𝟏/𝐜𝐨𝐬𝒚 = 1/(2𝑥^2 − 1) cos𝑦 = 2𝑥2−1 y = cos –1 (2𝑥2−1) Putting 𝑥 = cosθ 𝑦 = cos –1 (2𝑐𝑜𝑠2𝜃−1) 𝑦 = cos –1 (cos2 𝜃) 𝑦 = 2𝜃 Putting value of θ = cos−1
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If y = xx, prove that d2y/dx2 (1/y)(dy/dx)2 y/x = 0 Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queriesBernoulli's equation has form, \frac{dy}{dx}p(x)y=q(x)y^n Now, consider this, \frac{dz}{dx}z^2x=z^2z This easily simplifies to, \frac{dz}{dx}z=(1x^2)z^2 where p(x)=1 Find bounded solutions of this ODEHow can I solve it?
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Answer to Solve the initial value problem dy/dx = (y^2 1)/(x^2 1), y(2) = 2 By signing up, you'll get thousands of stepbystep solutions toLet's simplify it First dy/dx = (y/x 1)/(y/x 1) Taking y = vx dy/dx = v xdv/dx Therefore, dx/x = (v 1)dv / (v^2 1) Integrating we get log (1/x) logc45 (17) (39) (15) Choose An Option That Best Describes Your Problem Answer not in Detail Incomplete Answer Answer Incorrect Others Answer not in Detail Incomplete Answer
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Calculus Find dy/dx y=1/ (x^2) y = 1 x2 y = 1 x 2 Differentiate both sides of the equation d dx (y) = d dx ( 1 x2) d d x ( y) = d d x ( 1 x 2) The derivative of y y with respect to x x is y' y ′ y' y ′ Differentiate the right side of the equation Tap for more steps So variable separable method is not possible Now, 𝑑𝑦/𝑑𝑥 = ((1 𝑦^2))/tan^(−1)〖𝑦 − 𝑥〗 Put F(x, y) = 𝑑𝑦/𝑑𝑥 F(x, y) = (1 𝑦^2)/(tan^(−1)𝑦−𝑥) F(𝜆x, 𝜆y) = (1 𝜆^2 𝑦^2)/(tan^(−1)𝜆𝑦−𝜆𝑥)≠ 𝜆° F(x, y) Hence, the equation is not homogenous dy/dx=x/y x^2y^2=1 Differentiate wrt x d/dxx^2d/dxy^2=d/dx1 We already know how to deal with the first and third terms, so lets get them out the way d/dxx^2d/dxy^2=d/dx1 2xd/dxy^2=0 For the remaining term we use the chain rule, we don't know how to differentiate y^2 wrt x but we do know how to differentiate y^2 wrt y (it the same as differentiating x^2 wrt x!)
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y arctan(y) = x C We have dy/dx = 11/y^2 Which is a First Order Separable Ordinary Differential Equation so we can rearrange and "separate the variables" dy/dx = (1y^2)/y^2 => int \ y^2/(1y^2) \ dy = int \ dx We can manipulate the LHS integral \ \ \ \ \ int \ (1y^21)/(1y^2) \ dy = int \ dx int \ 1 1/(1y^2) \ dy = int \ dx Which is now trivial toIf y = (2x 1)3 find dy/dx If y = (2x 1)3 find dy/dx A 3(2x1)2 B 6(2x1) C 3(2x1) D 6(2x1)2 Correct Answer Option D Explanation y = (2x 1)3 dy/dx = 3(2x 1)31 x 2 = Past Question and answers for schoolworks Transcript Example 10 Find the general solution of the differential equation 𝑑𝑦/𝑑𝑥=(1 𝑦^2)/(1 𝑥^2 ) 𝑑𝑦/𝑑𝑥=(1 𝑦^2)/(1 𝑥^2 ) 𝑑𝑦/(1 𝑦2)=𝑑𝑥/(1 𝑥^2 ) Integrating both sides ∫1 𝑑𝑦/(1 𝑦^2 ) = ∫1 𝑑𝑦/(1 𝑥^2 ) (∫1 1/(1 𝑥^2 ) dx = tan−1 x c) tan−1 y = tan−1 x c tan−1 y = tan−1 x c is the
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